9x^2-1000=0

Solution for 9x^2-1000=0 equation:

9x^2-1000=0

a = 9; b = 0; c = -1000;
Δ = b2-4ac
Δ = 02-4·9·(-1000)
Δ = 36000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{36000}=\sqrt{3600*10}=\sqrt{3600}*\sqrt{10}=60\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{10}}{2*9}=\frac{0-60\sqrt{10}}{18}
=-\frac{60\sqrt{10}}{18}
=-\frac{10\sqrt{10}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{10}}{2*9}=\frac{0+60\sqrt{10}}{18}
=\frac{60\sqrt{10}}{18}
=\frac{10\sqrt{10}}{3}
$